Milos Raonic, Alexandr Dolgopolov and Marin Cilic were successful in the first round of Monte Carlo 2013 ATP tournament.
Twelfth seed Canadian Raonic put in a routine performance at the beginning of his Monte Carlo 2013 campaign. He stormed through the opening set of his first round duel with Frenchman Julien Bennetau as he opened the match by winning five consecutive games, including two breaks. The French player created a couple of break balls himself, yet he converted neither of them and Raonic went one nil up very easily. In the second set the four-time ATP title holder Canadian again held all of his service games, while he broke his rival in the fifth game and ultimately tucked away the match ball number one. Final result: 6-1, 6-4.
Ukrainian Dolgopolov was no less convincing as he ousted young Australian Bernard Tomic smoothly enough in straight sets. He confirmed his first break to move 3-1 ahead in the opener and added another one a few games later before serving out the set. His serve remained intact in the set number two as well, while he managed to break Tomic to love in the third game. The first match ball did the trick for Dolgopolov who progressed with a 6-2, 6-4 victory.
Ninth-seeded Croatian player Cilic was stretched to three sets by Horacio Zeballos of Argentine, yet he avoided an early Monte Carlo exit in the end. He wrapped up the opener after achieving a double break advantage, while both of the players suffered three losses of serve in the set number two which thus went to a tie-break – Zeballos held his nerves and made it one set each. However, the decider was all about the Croat who went two breaks up again before sending Zeballos home with a 6-2, 6-7 (6), 6-2 victory.