Kamila Kerimbayeva vs Anastasia Kharchenko Head To Head
Kerimbayeva Kharchenko H2H Stats & Matches...


Share This...

Do A New Men's Head To Head Search!

Player1 Player2  

Do A New Women's Head To Head Search!

Player1 Player2  

H2H Results For Kerimbayeva Kharchenko:

1
Wins
1
Kamila Kerimbayeva
Name
Anastasia Kharchenko
492
Ranking
1995-06-18
Birth Date
1989-12-12
Kazakhstan
Nationality
Ukraine
Plays

Head To Head Matches - Chat About The Kamila Kerimbayeva vs Anastasia Kharchenko Head To Head

YearNameRoundSurfaceWinning Player Losing PlayerScore
201310k Sharm El Sheikh, Wk. 21QFHardAnastasia Kharchenko Kamila Kerimbayeva6-2 7-5
201210k Bogota, Wk. 38QFClayKamila Kerimbayeva Anastasia Kharchenko6-3 6-0

Kamila Kerimbayeva Last 10 Matches:

201510k Shymkent, Wk. 18R32ClayL Viktoryia Mun1-6 6-3 6-3
201510k Shymkent, Wk. 17SFClayL Ksenia Palkina5-7 7-5 7-6(4)
201510k Shymkent, Wk. 17QFClayW Liubov Vasilyeva6-3 6-3
201510k Shymkent, Wk. 17R16ClayW Albina Khabibulina7-6(3) 6-3
201510k Shymkent, Wk. 17R32ClayW Aleksandra Pospelova7-5 6-3
201525k Karshi, Wk. 15R16HardL Olga Puchkova6-7(3) 6-4 6-3
201525k Karshi, Wk. 15R32HardW Arina Taluenko6-0 6-1
201510k Antalya, Wk. 13R16HardL Caroline Romeo6-4 6-3
201510k Antalya, Wk. 13R32HardW Anna Maria Heil7-5 6-3
201510k Antalya, Wk. 12R16HardL Aryna Sabalenka1-6 6-1 6-2

Anastasia Kharchenko Last 10 Matches:

201510k Sharm El Sheikh, Wk. 18R32HardL Yulia Bryzgalova6-3 6-1
201510k Sharm El Sheikh, Wk. 11FHardL Xiao Xuan Guo6-2 6-4
201510k Sharm El Sheikh, Wk. 11R16HardL Luisa Marie Huber7-5 6-2
201510k Sharm El Sheikh, Wk. 11R32HardW Prarthana G. Thombare6-4 1-6 6-3
201510k Sharm El Sheikh, Wk. 10R16HardL Vera Lapko6-1 6-4
201510k Sharm El Sheikh, Wk. 10R32HardW Luisa Marie Huber6-0 6-1
201510k Sharm El Sheikh, Wk. 9R32HardL Vojislava Lukic6-2 6-1
201410k Djibouti, Wk. 50R32HardL Magali KempenWO
201410k Djibouti, Wk. 49R16HardL Harriet Dart6-7(9) 6-2 6-1
201410k Djibouti, Wk. 49R32HardW Ivana Horvat6-1 6-2

Whats your opinion on the head to head? Is a better tennis player?