Martin Lee vs Neil Bamford Head To Head
Bamford Lee H2H Stats & Matches...


Share This...

Do A New Men's Head To Head Search!

Player1 Player2  

Do A New Women's Head To Head Search!

Player1 Player2  

H2H Results For Bamford Lee:

0
Wins
3
Neil Bamford
Name
Martin Lee
x
Ranking
x
1982-02-10
Birth Date
1978-01-13
Great Britain
Nationality
Great Britain
Unknown
Plays With
Left

Head To Head Matches - Chat About The Neil Bamford vs Martin Lee Head To Head

YearNameRoundSurfaceWinning Player Losing PlayerScore
2006Great Britain F13 FuturesQFHardMartin Lee Neil Bamford6-7(5) 6-4 6-4
2005Great Britain 4R16HardMartin Lee Neil Bamford7-5 7-6(5)
2005Great Britain 3R32HardMartin Lee Neil Bamford6-7(4) 6-3 6-1

Neil Bamford Last 10 Matches:

2008Jersey ChallengerQHardL Andreas Haider-Maurer6-4 6-4
2008GREAT BRITAIN F18 FUTURESR16HardL Jean-Noel Insausti7-5 6-1
2008GREAT BRITAIN F18 FUTURESR32HardW Petru-Alexandru Luncanu6-4 6-3
2008GREAT BRITAIN F17 FUTURESR32HardL Pierre Metenier6-2 4-6 7-5
2008GREAT BRITAIN F16 FUTURESR32HardL Sean Thornley6-2 6-2
2008Great Britain F13 FuturesR32HardL Dayne Kelly6-3 3-0 Retired
2008Great Britain F12 FuturesQFHardL Marcus Daniell6-4 2-1 Retired
2008Great Britain F12 FuturesR16HardW Tim Hewitt6-4 7-5
2008Great Britain F12 FuturesR32HardW Maniel Bains6-3 2-6 6-4
2008Great Britain F11 FuturesQFGrassL Daniel Cox4-6 7-6(3) 7-6(9)

Martin Lee Last 10 Matches:

2006Rennes ChallengerR32CarpetL Dick Norman7-6(5) 6-4
2006Grenoble ChallengerR32HardL Cyril Saulnier6-2 7-5
2006Great Britain F13 FuturesSFHardL Rameez Junaid6-3 6-3
2006Great Britain F13 FuturesQFHardW Neil Bamford6-7(5) 6-4 6-4
2006Great Britain F13 FuturesR16HardW Thomas Greenland6-1 6-2
2006Great Britain F13 FuturesR32HardW Kyle Brassington6-0 6-0
2006Orleans ChallengerR32HardL Ernests Gulbis6-3 6-4
2006US OpenQHardL Bohdan Ulihrach6-3 6-7(4) Retired
2006Bronx ChallengerR32HardL Yen-Hsun Lu7-5 6-1
2006Bronx ChallengerQHardL Andrea Stoppini6-2 6-3

Whats your opinion on the Bamford Lee head to head? Is Bamford a better tennis player?