Julien Benneteau vs Oscar Hernandez Perez Head To Head
Benneteau H2H Stats & Matches...


Share This...

Do A New Men's Head To Head Search!

Player1 Player2  

Do A New Women's Head To Head Search!

Player1 Player2  

H2H Results For Benneteau :

3
Wins
1
Julien Benneteau
Name
Oscar Hernandez Perez
44
Ranking
1395
1981-12-20
Birth Date
France
Nationality
Right
Plays With

Head To Head Matches - Chat About The Julien Benneteau vs Oscar Hernandez Perez Head To Head

YearNameRoundSurfaceWinning Player Losing PlayerScore
2009KitzbuhelSFClayJulien Benneteau Oscar Hernandez Perez6-3 6-4
2009Monte Carlo MastersR64ClayOscar Hernandez Perez Julien Benneteau6-4 6-4
2008CasablancaQFClayJulien Benneteau Oscar Hernandez Perez6-3 5-2 Retired
2007New HavenR64HardJulien Benneteau Oscar Hernandez Perez6-2 6-2

Julien Benneteau Last 10 Matches:

2014WimbledonR128GrassL Gilles Muller6-4 7-6(6) 7-6(5)
2014EastbourneQFGrassL Sam Querrey7-6(5) 6-4
2014EastbourneR16GrassW Gilles Simon6-3 6-4
2014EastbourneR32GrassW Yen-Hsun Lu6-2 6-4
2014QueensR64GrassL Victor Estrella Burgos6-7(3) 6-3 7-6(3)
2014French Open - Roland GarrosR128ClayL Facundo Bagnis6-1 6-2 1-6 3-6 18-16
2014NiceR32ClayL Carlos Berlocq6-1 4-6 6-3
2014Bordeaux ChallengerFClayW Steve Johnson6-3 6-2
2014Bordeaux ChallengerSFClayW Kenny De Schepper6-4 3-6 6-3
2014Bordeaux ChallengerQFClayW Jiri Vesely6-7(4) 7-5 6-3

Oscar Hernandez Perez Last 10 Matches:

2014WimbledonQGrassL Toni Androic6-4 6-3
2013Cambodia F2 FuturesR32HardL Takashi Saito7-5 6-0
2013Cambodia F1 FuturesQFHardL Hiroki Kondo5-2 Retired
2013Cambodia F1 FuturesR16HardW Harry Meehan3-6 6-3 6-2
2013Cambodia F1 FuturesR32HardW Katsushi Fukuda7-6(6) 6-3
2010Napoli Challenger 2R16ClayL Potito Starace5-7 6-2 7-6(5)
2010Napoli Challenger 2R32ClayW Daniel Munoz-De La Nava6-1 6-2
2010Trnava ChallengerR16ClayL Jaroslav Pospisil6-2 5-7 6-1
2010Trnava ChallengerR32ClayW Marko Danis6-2 6-1
2010Todi ChallengerQFClayL Alessio Di Mauro6-1 6-2

Whats your opinion on the Benneteau head to head? Is Benneteau a better tennis player?