2015 may bring bittersweet fortunes for Nick Kyrgios, as the rising prospect may be faced with a troubling injury while at his home slam. After his slow start to the season, he will hope to be ready to begin his campaign in Melbourne, which he will kick off against Argentina’s Federico Delbonis. Only seven spots separates the two competitors in the rankings and this is also their first professional meeting on the tour.
After taking part in the International Premier Tennis League in the off-season, Nick Kyrgios, who shot to stardowm with an upset of Rafael Nadal at Wimbledon last year, began his season against Jerzy Janowicz in Sydney, where he witnessed the Polish No. 1 rally from a set down to beat him 6-1 6-7(6) 7-6(5). Following the match, it became clear that Kyrgios had suffered a back injury.
However, it seems that he is well on his way to a full recovery – or at least that is what he told reporters.
“Uhm, yeah, I’m noticing improvements every day. I’ve done everything I possibly can to get where we can get the most improvement. Yeah, I think I’m ready to compete.
“Sometimes you can’t avoid injuries. It’s just part of the game. I’ve done everything I can with my physios, my training. Been monitoring training. I’m think that I’m confident I can still make a pretty big impact.”
The Australian will come up against Federico Delbonis, who began his season with a 6-1, 6-1 loss to Frenchman Adrian Mannarino in Auckland.
“He obviously plays some pretty solid tennis,” Kyrgios said of his upcoming opponent. “He’s obviously had a good year. I’m just going to go out there, have fun. You know, obviously night match on Margaret Court Arena again. I’m really looking forward to that. He’s going to be playing some really solid tennis. I know I have to play aggressively and take it to him.”
This marks the first time that these two competitors will meet on the professional tour, and will likely be a contest that Kyrgios shoud win in under five sets. However, given his recent injury, anything can happen.
Prediction: Nick Kyrgios in Four Sets