Following a surprisingly dominant performance against Swiss superstar Roger Federer, Milos Raonic is through to the semi-final round in Paris, and with momentum on his side, he will look to down Czech No. 1 Tomas Berdych in their fourth career encounter. The Raonic v Berdych head-to-head series stands at 2-1.
For the first time in seven meetings, Milos Raonic managed to pick up his first ever victory over Roger Federer to deny the world No. 2 a shot at the year-end top spot ranking, while simultaneously qualifying for the Barclays ATP World Tour Finals. The contest lasted a total of 1 hour and 33 minutes, where the Canadian struck 21 aces en route to the impressive win.
“It would have to be up there definitely at this stage of my career, with the level I have gotten myself to, that’s for sure,” commented Raonic on the upset victory. “And considering all the circumstances around it, I think this was the biggest win for me.”
“I’m very motivated,” Raonic added, referring to his performance in the Emirates ATP Race To London. “I think I have been sort of trying to find this level; fortunately I have been able to do so this week. I definitely struggled the last few weeks. If it wasn’t sort of me biting away the whole time and having that kind of motivation to need and to want to do well here, I don’t think I’d find the answers that I have this week.”
Tomas Berdych rallied from a set down to defeated South Africa’s Kevin Anderson 6-7(4), 6-4, 6-4 and book his own spot in the year-end championships.
“No matter how many times you [qualify], it’s probably never going to be a routine thing,” said Berdych. “It’s always just proof of having a great season, and especially in this era of tennis… you kind of fight for only four spots, I would say.”
This marks the fourth time that these two competitors will meet on the professional tour, with Raonic leading the series 2-1. Based on his dominant showing against Federer, the momentum will be in the Canadian’s favour to close defeat his Czech adversary.
Prediction: Milos Raonic in Three Sets