David Ferrer is through to his fifth consecutive fourth round match-up at the Sony Open, where he will meet Japanese No. 1 Kei Nishikori for a sixth time on the ATP tour. The Ferrer Nishikori head-to-head series stands at 3-2, with the Spaniard having won their most recent encounter at last year’s Round of the 16 in Miami.
World No. 4 David Ferrer cruised into the fourth round with a comfortable 6-3, 6-2 victory over Italy’s Andreas Seppi. The Spaniard hit 1 ace, 2 double faults and only 50% of his first serve, yet still managed a comfortable win in 69 minutes. The win also extends his h2h against Seppi to 6-0 without dropping a single set against the Italian. He is now through to his fifth consecutive fourth round in Miami, and will be looking to make it four consecutive quarter-finals when he faces Kei Nishikori on Tuesday.
Kei Nishikori defeated Grigor Dimitrov in a tight third round contest at the Sony Open on Sunday. While the budding Bulgarian talent struck more aces and winners during the contest, it was Nishikori’s consistency on his serve and his lack of errors that eventually made the difference in the match. Dimitrov made 28 errors during the match and allowed one break point to get past him in the final game, which ultimately cost him the match. Nishikori is now through to the Round of the 16 for the third consecutive time.
Ferrer and Nishikori have met on five occasions on the professional circuit, with the fourth seed holding a slight 3-2 lead in the series. Ferrer won their two most recent encounters – both of which took place on hard courts in 2013. Nishikori’s win came at the London Olympic games and the 2008 US Open. Ferrer will be considered the favourite ahead of this match-up, yet the result will be determined by his consistency and performance on court and not simply by his lead in the h2h series.
Prediction: David Ferrer in Three Sets